ZacKenichi
02/04/2025, 4:28 AMVapi
02/04/2025, 4:29 AM/inbound-calls, and configure your Voice API account to send incoming call notifications to this endpoint.
Once you have your endpoint set up, you can write logic to handle the incoming call event and route it to an agent. This could involve answering the call, playing a greeting, and then connecting the caller to an agent's extension or phone number.
If you need to provision a new phone number and set up inbound calling, you would typically use the Voice API's management console or an API call to provision the number and configure the routing.
If you need assistance with the specific steps or code to set up inbound calling for your agent, please let me know, and I can provide more detailed guidance.ZacKenichi
02/04/2025, 4:30 AMVapi
02/04/2025, 4:30 AMZacKenichi
02/04/2025, 4:50 AMVapi
02/04/2025, 4:50 AMZacKenichi
02/04/2025, 6:43 AMVapi
02/04/2025, 6:43 AMbash
curl --request GET \
--url 'https://api.yourvoiceapi.com/calls?phoneNumber=customerPhoneNumber&orderBy=startTime&order=desc&limit=1' \
--header 'Authorization: Bearer YOUR_API_TOKEN' \
--header 'Content-Type: application/json'
In this template:
- Replace https://api.yourvoiceapi.com/calls with the actual API endpoint for retrieving call records.
- Replace customerPhoneNumber with the phone number of the customer whose last call you want to retrieve.
- Replace YOUR_API_TOKEN with your actual API token or authentication credentials.
- The orderBy=startTime&order=desc&limit=1 part of the URL assumes that the API allows you to sort the calls by start time in descending order and limit the results to the most recent call.
Please note that the actual parameters and the endpoint will vary based on your Voice API provider's documentation. If you can provide the name of your Voice API provider or if you have the API documentation available, I can help you construct the exact cURL command you need.
If you're ready to proceed with the cURL command and need assistance with the specific parameters or authentication method, please let me know, and I'll be happy to help.ZacKenichi
02/04/2025, 6:43 AMVapi
02/04/2025, 6:43 AM